Are wheel spacers any good for a Discovery 2004
Hi everyone;
I am new to this forum. I need some help with regards to upgrading my Discovery (SE 2004) with wheel spacers. I think it can help with stability and CG issues.
Does anyone have experience with these?
Thanks
Hurricane Moon
Miami, FL
I am new to this forum. I need some help with regards to upgrading my Discovery (SE 2004) with wheel spacers. I think it can help with stability and CG issues.
Does anyone have experience with these?
Thanks
Hurricane Moon

Miami, FL
Stephen
If you are meaning that you want to upgrade to wheel spacers I would agree with the post above that you would be better off just getting wheels with more of an offset. My experience with wheel spacers are that they put more torque on the hub and wheel bearing since it makes the wheel sit further away( the longer the wrench the more torque you can put on something, kind of works the same way) and since these have issues with wheel bearing going out or just even leaking I would want to stay away from putting more torque on the hubs if possible. Just my two cents, I guess.
Not much difference between spacers pushing the wheel further out and larger offsets. The main difference is it's just once less thing to faff with, fewer lug nits to worry about and no need to worry about getting sub-par spacers.
I appreciate the your input, it explains why I should not. I never thought of the torque issue. I just love this machine (D2, 2004 SE) and in Florida hurricanes are a real issue. I want to prep mine with every little advantage I can get. After a major storm (CAT 3 and above), roads become obstacle courses for vehicles.
I'm planning on getting an A frame bumper (ARB WINCH BAR) with the winch and two sets of off-road lights. Fortunately, I was able to get my D2 on springs, and it sits tall.
Stephen
Miami, FL
I'm planning on getting an A frame bumper (ARB WINCH BAR) with the winch and two sets of off-road lights. Fortunately, I was able to get my D2 on springs, and it sits tall.
Stephen
Miami, FL
WHAT IS TORQUE?
Torque is a measure of how much a force acting on an object causes that object to rotate. The object rotates about an axis, which we will call the pivot point, and will label 'O'. We will call the force 'F'. The distance from the pivot point to the point where the force acts is called the moment arm, and is denoted by 'r'. Note that this distance, 'r', is also a vector, and points from the axis of rotation to the point where the force acts. (Refer to Figure 1 for a pictoral representation of these definitions.)
With that being said, lets say that the few inches that seperate the hub bearing and the lug nuts do not exist and the pivot point is the front of the hub (which it is not). Lets do some math.
If you are planning on putting 2" spacers on your discovery. The discovery weighs 4707 lbs. And if the weight was evenly distributed to each wheel (which 2/3 of the weight is on the front 1/2 of the car) but for math lets say it is, each wheel would be supporting 1176.75 lbs. Torque is measured in Newton-meters so we will so the conversions.
2" spacers=0.0508 M
1176 lbs= 22561.138 N
sin90=weight being forced on the hub at a 90 degree angle from ground.
M*N*sin90=Torque
0.0508(22561.138)(sin90)=1024.615NM
1NM=0.737562149 ft/lbs
thus: a 2" spacer puts an extra 188.92 pounds of foot torque on your hubs and wheel bearings.
And as for the offset, it doesn't make a difference of the offset on the torque because the wheel bolts the same distance from the hub (doesn't matter where the rim or where the tire is compared to the lugs) The lug holes are only so thick. The torque is added when you move the distance further away from the hub by adding more of a leverage arm.
Sorry for going on a tangent but it was bothering me that you didn't believe me when I do know what I am talking about.

Torque is a measure of how much a force acting on an object causes that object to rotate. The object rotates about an axis, which we will call the pivot point, and will label 'O'. We will call the force 'F'. The distance from the pivot point to the point where the force acts is called the moment arm, and is denoted by 'r'. Note that this distance, 'r', is also a vector, and points from the axis of rotation to the point where the force acts. (Refer to Figure 1 for a pictoral representation of these definitions.) With that being said, lets say that the few inches that seperate the hub bearing and the lug nuts do not exist and the pivot point is the front of the hub (which it is not). Lets do some math.
If you are planning on putting 2" spacers on your discovery. The discovery weighs 4707 lbs. And if the weight was evenly distributed to each wheel (which 2/3 of the weight is on the front 1/2 of the car) but for math lets say it is, each wheel would be supporting 1176.75 lbs. Torque is measured in Newton-meters so we will so the conversions.
2" spacers=0.0508 M
1176 lbs= 22561.138 N
sin90=weight being forced on the hub at a 90 degree angle from ground.
M*N*sin90=Torque
0.0508(22561.138)(sin90)=1024.615NM
1NM=0.737562149 ft/lbs
thus: a 2" spacer puts an extra 188.92 pounds of foot torque on your hubs and wheel bearings.
And as for the offset, it doesn't make a difference of the offset on the torque because the wheel bolts the same distance from the hub (doesn't matter where the rim or where the tire is compared to the lugs) The lug holes are only so thick. The torque is added when you move the distance further away from the hub by adding more of a leverage arm.
Sorry for going on a tangent but it was bothering me that you didn't believe me when I do know what I am talking about.


